$1x^2-4$
$f\left(x\right)=\left(x^2-x\right)\:\left(x+2\right)$
$\lim_{x\to-\infty}\left(\frac{4x^2+x^2+5}{3x^5+x^3-x}\right)$
$7x^2+25x-12$
$\left(2x+1\right)\left(3x+2\right)$
$-4\cdot2-\left(-14\right)$
$\left(64c^8\right)^{-\frac{5}{6}}$
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