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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=5$, $b=-160$ and $c=1200$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{160\pm \sqrt{{\left(-160\right)}^2-4\cdot 5\cdot 1200}}{2\cdot 5}$
Learn how to solve problems step by step online. Find the roots of 5x^2-160x+1200=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=5, b=-160 and c=1200. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 160 and -40.