$\int\frac{y^4+8}{y^3+2y^2}dy$
$\int40x\left(x^2+1\right)dx$
$20-35n^2-20n^3$
$\left(3\sqrt{xy}\right)\left(-2\sqrt{x^2}y\right)\left(-3\sqrt{xy^4}\right)$
$-h^3+4h^2-5h+2$
$\frac{dy}{dx}=\:36x\:+\:42y\:-\:4x^2\:-\:2xy\:-\:4y^2\:-\:20$
$\frac{dy}{dx}=\:3+7y$
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