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$\left(4^3\right)^{-2}$
$\left|\frac{-12-3}{-6+3}\right|$
$-1.3-\left(4.9+2.6\right)$
$\int6x\left(6x^2+2\right)dx$
$\left(x\left(\sqrt{9-x^2}+\sqrt{4-x^2}\right)\right)$
$3x+y=8$
$\int\left(5x-3\right)^4\ln\left(x-1\right)dx$
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