$\left(-1\right)^3+3\left(-1\right)^2+2\left(-1\right)$

$\left(1+\sin\alpha\right)\left(1-\sin\alpha\right)$

$6.\left(-1\right)^3-3^2.2:\sqrt{6^2}$

$3\tan^2\left(a\right)=\sec^2\left(x+1\right)$

$14u-11u+u-4u+4u=20$

$\frac{x^3+x}{x^2-x}$

$10+x>\frac{4}{5}\left(25+x\right)$