$\int_{-2}^4\frac{x^2+4}{x^2+1}\:dx$
$\int x^2e^{3x}da$
$\lim_{x\to0}\left(\frac{2\cos\left(4x\right)-4x^2-2}{\sin\left(2x\right)-x^2-2x}\right)$
$x^2-18x+81=0$
$-6x+2-4x+38$
$x-5>3x$
$\left(2x+y+32\right)^2$
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