$\:\left(-\:\frac{4}{3}x+4\right)^2$
$\left(12c+15d\right)^2$
$2x^2+7+6x-1-7x-6x^2$
$-\frac{27}{x^3-3x^2}$
$a^3+\left(\frac{1}{3}\right)^3$
$9n^2+3nd+25nd^2$
$-5-9-7x+6x$
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