$\frac{\left(1-2x\right)}{\left(x^2-2x-3\right)}\ge1$
$\left(a-3\right)\left(b+9\right)$
$4x+6<15-25x$
$9b\left(x^3-y^2\right)-7c\left(x^3-y^2\right)$
$\frac{\left(25x^2-36y^2\right)}{5x-6y}$
$\:-2.\:\frac{1}{2}\:+\:5$
$4^{x+1}=16^{2x-1}$
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