$\left(a^{2}b\right)\left(a^{2}\right)$
$x\left(x+1\right)^2\left(x+2\right)=0$
$\int\frac{\left(3x+2\right)}{\left(x^2-4\right)}dx$
$\frac{1}{x+3}+\frac{1}{x^2-9}$
$\frac{dp}{dt}=0.0009p$
$17-13+67+3+8+13-2$
$x^2-10x+19=0$
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