$\int\left(x^3\left(x^2+1\right)^3\right)dx$
$\frac{1}{6m}+\frac{2}{5m}+\frac{4}{m}$
$xy'=\sqrt{xy}+y$
$\int\frac{\left(x^{10}\right)}{\left(16-x^2\right)^{\frac{13}{2}}}dx$
$f\left(x\right)=\ln\frac{x^3+3}{x^4}$
$-4\left(-6\right)\cdot\left(5-13\right)$
$3x-2>x+5$
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