$\sqrt{27}+5\sqrt{3}-2\sqrt{12}$
$2x+5>3-7x$
$\frac{1}{y^2}y'\:=-2x$
$\frac{dx}{dt}=t^3-t$
$\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)$
$\left(3a^4b^3\right)^6$
$4n^2\:-\:24n\:+\:36$
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