$\frac{\sqrt{x}-2}{x-4}\lim_{x\to0}\left(4\right)$
$\left(x^4+81\right)\left(x^2+9\right)\left(x+3\right)\left(x-3\right)$
$\int\frac{x}{\sqrt[3]{4\:-3x}}dx$
$-4\cdot\left(-19\right)\cdot\left(-15\right)$
$\frac{x^5y^2}{x^4y^3}$
$6y+5-7y-2$
$\left(10x-2\right)\:\left(10x+2\right)$
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