$6x^3y-2x^2=8$
$-2x^2-8x+3-9x^2+x+3$
$\left(3x^3-2y\right)^5$
$\frac{x^2+13x+40}{x+8}$
$\left(a+5b\right)\left(a+3b\right)$
$\frac{-1}{16\left(x-3\right)}$
$52k^2-48h^2+128hk+288h+416k+768$
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