$\ln\sqrt{x}-\frac{1}{6}\ln x+\ln\left(\sqrt[5]{x}\right)$
$\frac{x^2+4x-3}{x-3}=3$
$-2\frac{4-3x}{5}$
$\frac{3x}{\sqrt{2}}$
$y=-2y$
$\frac{\left(1+\cos\:\left(x\right)^2\right)}{\sqrt{x}}$
$\lim_{x\to0}\left(\frac{a^x-b^x}{x^1}\right)$
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