$\int_1^{\infty}\left(\frac{18x}{x^2+3}\right)dx$
$8\left(y\right)^{''}+4\left(y\right)^'+5y=0$
$t\cdot ln\left(s^{2t}\right)+8t^2$
$\left(2x+2h+3\right)^2$
$\left(6x-3\right)\left(6x-4\right)$
$\left(2x-12\right)\left(8x+1\right)$
$5b^3-20b^2+4b$
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