$9,3\:-\:5,08$
$\frac{1+sin2x}{cos2x}$
$1-x^8$
$-3^2+6\cdot3-8$
$\int x\cos\left(\frac{1}{3}\right)dx$
$x ^ { 4 } - 2 x ^ { 3 } - 5 x ^ { 2 } + 6 x$
$a^3-8a^2+16a$
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