$\frac{x-3}{2}=\frac{x}{5}$
$-3^2\cdot\left(-6^1\right)$
$f\left(x\right)=\frac{2x^2-\left(4x^2-6x\right)}{x^4}$
$-3x+3=2x+8$
$\left(x-2\right)\left(x+5\right)+\left(x-2\right)\left(x+8\right)$
$5y^2-8y=2$
$25^2+60+36^2$
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