$\lim_{x\to\infty}\left(\frac{cos\left(13x\right)}{13x}\right)$
$3x-8>13$
$\frac{6x^3}{\:3x^6}$
$6\lim_{x\to2}\left(\frac{x^{2}-4}{3x-6}\right)$
$1^2mn^2z^2a$
$\frac{9a^4b^2-16a^2b^6}{3a^2b-4ab^2}$
$\frac { 4 } { x } = - 1$
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