$\left(2x+3\right)\left(4x^2+2-6x\right)$
$\int3^{4x^3}x^2dx$
$\left(x+\frac{5}{3}\right)^2$
$12x^2-19x-5$
$\left(\frac{m^2}{4}+5\right)^3$
$99-23+\left(-104\right)-\left(-55\right)$
$-\frac{\left(-\sin\left(x\right)\right)}{\cos^2\left(x\right)}=\sec\left(x\right)\tan\left(x\right)$
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