$\left(5x^2+\sqrt{3}\right)^3$
$z=\arcsin\left(x-y\right),\:x=s^2+t^2,\:y=1-2st$
$\lim_{x\to2}\left(\frac{4x-8}{x^2-4}\right)$
$\left(3x-4\right)-\left(6x-8\right)$
$x^2+12>8x$
$3\left(x-1\right)=9$
$3x^2-18x+15$
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