$\left(2x^6-3\right)^3$
$a^2+a^2+1$
$\int\frac{\left(3x^2+2x-13\right)}{\left(\left(x-3\right)\left(x^2+1\right)\right)}dx$
$3x^3+9xy^2=9x^3$
$\frac{5x^4-3x^3+6x^2-6}{x+2}$
$\left(-x-9\right)\left(-x-2\right)$
$\int_{-20}^{\infty}1dx$
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