$14-12+45-23+1$
$13x\:+\:4y\:+\:2x$
$\frac{\left(x^3+2x-15\right)}{\left(x-2\right)}$
$12+x^2<0$
$16\cdot4^4$
$x\left(x-1\right)+\left(x-1\right)$
$\left(4a^2b^2-b\right)\left(3abc+b\right)$
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