$0.3\cdot8$
$\frac{20}{4}$
$\lim_{x\to\infty}\left(\sqrt[x]{4x+2}\right)$
$5x-8<12$
$\left(\frac{x^{-2}y^3}{x^4y^{-1}}\right)^4\left(\frac{x^{-2}y^3}{x^4y^{-1}}\right)^2$
$x^3+5x^2-9x=0$
$\left(x-7y\right)\left(x+4y\right)$
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