$\lim_{x\to4}\left(2x-7\right)^{\frac{1}{4x-16}}$

$\lim_{x\to0}\left(\frac{tan\left(3x^2\right)+sin^2\left(8x\right)}{x^2}\right)$

$series\:ln\left(1-8x\right)$

$4563-8765$

$3x^2-22x+35=0$

$\lim_{x\to\infty}\left(\cos\left(x\right)\ln\left(\tan\left(x\right)\right)\right)$

$12x^5+2x^2+6x$