$x^2\le2x-9$
$\lim_{x\to-2}\left(\frac{x^3+4x^2+4x}{\left(x+2\right)\left(x-3\right)}\right)$
$2x^2-8x+3$
$\left(x-25\right)\left(x+12\right)$
$\left(-15\right)\left(-25\right)\left(-35\right)$
$3x^3-20x^2+37x-20$
$2^2+2x+c$
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