$\lim_{x\to2}\left(x^3-2x^2+18\right)$
$\frac{a^6-27b^3}{a^2-3b}$
$\left(2x^2+6x-3\right)-\left(x^3+2x^2-2\right)$
$2\log\left(c\right)+3\log\left(k\right)$
$x2\:+\:9x+\:81=0$
$3^2+\left(2+3^3\right)$
$99,9999999999999+100$
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