$\frac{x+3}{1-x}=\frac{x+1}{x+2}$
$-3y<-15$
$sen^2\theta\:-2sen\theta\:=0$
$\sin\left(\tan^{-1}\frac{x}{6}\right)$
$y+3=x^2+16x\:+64$
$10x^2+28xy$
$3\left(2.001\right)^4-5$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!