$\frac{6}{6yx}$
$\frac{6x^5y^4}{4y^3x^6}$
$\lim_{x\to3}\left(\frac{x^2-6x+9}{2x-6}\right)$
$\left(4x+5\right)\left(5x-2\right)$
$\tan^2x+5=\sec^2x+4$
$12.1\cdot3.8$
$\tan\left(x+1\right)=1$
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