$\int\left(-\frac{10x^4}{x^5+4}\right)dx$
$\left(3x^2-2x\left(3x^2+2y\right)\right)$
$9.z.y-3.z.y$
$-17+7\left(-7\right)-\left(-5\right)+\left(-10\right)-\left(-2\right)+4-57$
$\ln e^{3x}=15$
$23-\left(-23\right)$
$\frac{dy}{dx}=\frac{\left(y^2+y\right)}{x}$
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