$5x^2+5y^2+10x-5y+3=0$
$\frac{x^2-3x-10}{x^2-8x+15}$
$\frac{dy}{dx}+y=x,\:y\left(0\right)=4$
$\lim_{x\to1}\left(\frac{\left(x^2+4x-5\right)^{\frac{1}{2}}}{\sqrt{x^2-4x+3}}\right)$
$\frac{20x^3-5x^2+10x}{10x^2}$
$x^{a+1}\cdot x^{a-1}$
$\frac{dy}{dt}=x^2+\frac{1}{25}$
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