$\int\frac{\left(4-x\right)^3}{x}dx$
$\frac{dz}{da}=-8y$
$x^2+16x+4$
$\left(x^{n+1}-x\right)\left(x^{2n+2}+x^{n+2}+x^2\right)$
$5x-3\le6+x$
$-x^2+1\ge0$
$\left(-62+3\right)-\left(54-8\right)$
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