$\lim_{x\to0}\left(3x-1\right)$
$615+x^2=2^y$
$\frac{dx}{dy}-y^2+1=0$
$\frac{\left(x+3\right)+\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}$
$\left(2x^2-3\right)\left(2x^2+4\right)$
$\left(\frac{4y^2}{3}+5\right)\left(\frac{4y^2}{3}-5\right)$
$-1x+2x+7+-3x+-11$
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