$\frac{x^5\cdot x^{-3}}{x^{-5}}$
$8j-9=5j+18$
$7\left(8h\:-\:13\right)\:+\:6h\ $
$\left(25\:+\:16\:-\:37\right)\:-\:\left(-1\:-\:58\:+\:13\right)$
$\left(3x^3-7x^2-2x\right)\left(xy\right)$
$x^2-2x-4>0$
$1-\frac{\sin^2x}{1+\cos x}=0$
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