$\frac{d}{dx}\frac{1}{x}-\frac{1}{y}=0$
$\frac{3-ixi}{7}\le-2$
$\frac{\sin\left(x\right)-sin^3\left(x\right)}{\cos\left(x\right)}=\tan\left(x\right)cos^2\left(x\right)$
$\int-2x^2\left(3x^3+7\right)^2dx$
$y'=7x+y$
$\left(2\right)^{-4}\cdot2$
$x^2+0xy+36y^2$
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