$x\left(1+\cot^{2}x\right)$
$9x\cdot9$
$\frac{4x-2}{x\left(x-1\right)\left(x+2\right)}$
$\left(\frac{2}{3-x}+\frac{3}{x-3}\right)$
$x^2-3x-4\ge0$
$\left|54\right|$
$\frac{sec\:x\:+\:tan\:x\:}{cos\:x+cot\:x}\:=sec\:x\:.\:tan\:x$
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