$\left(7q^2w^2-4w^2\right)^2$
$06,489+51.400$
$\:-1\:+2\left[\:-3-\left(2-5\right)\:+3\:\right]-2\:$
$\frac{15}{16}x^2-\frac{21}{40}x^3-\frac{9}{28}x$
$\frac{x^3-x^4}{x^{-2}}$
$\left(-26+12\right)+\left(18-\left(16-9\right)\right)+\left(4-6\right)$
$3-6-2+5+2+6$
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