$\frac{dx}{\left(1+x^2\right)}+\frac{dy}{\left(1+y^2\right)}=0$

$cosx=\frac{1}{2};0\le x\le2x$

$q^{-3}.q^8.q^8$

$2\left(6\right)^4+3\left(7\right)^2-4\left(7\right)+5\left(6\right)$

$32-3.2$

$\left(5+b\right)\left(b-5\right)\left(b-3\right)\left(3+b\right)$

$\left(ln\left(y\right)\right)^5\:\frac{dy}{dt}=t^5y$