$\frac{\left(21-24\right)^3}{-11-4\left(4\right)}$
$\left(-150\right).-10$
$+2+-10$
$\left(3m-5n\right)\left(2n-4\right)$
$\left(150a^2b^3\right)^2$
$\lim_{x\to+\infty}\left(\frac{x\left(2+\sin\left(6x\right)\right)}{x+1}\right)$
$\frac{d}{dx}\:9^xln\left(x\right)$
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