$\frac{3x^2+5x-4}{x+3}$
$\left(a+4\right)-\left(6-9a\right)-\left(3a-7\right)$
$\left(x-5\right)^2\ge0$
$x^2+4x>4$
$36-\left(-30\right)$
$\frac{d}{dx}x^2+y^3=5$
$x^3-3x^2-10+24$
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