$\frac{\sin\left(x\right)-1}{\sin^2x}=\csc\left(x\right)-\csc^2x$
$-2y-xy+x^2-y$
$\lim_{x\to5}\frac{x^2-5x-24}{x^2-3x-18}$
$\frac{m^2-16}{m+4}$
$-50+65-1.600$
$\frac{-2x^3y}{x^2}$
$y=\frac{4x^{2}-16}{x-2}$
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