$\int\frac{6}{x\left(\ln\left(6x\right)\right)^5}dx$
$\int6\left(6x-5\right)^4dx$
$\sqrt{x+4a}-\sqrt{x+2a-1}=1$
$x'=3xt^2-3t^2$
$\left(\sqrt[3]{x+1}\right)\left(\sqrt[3]{x-1}\right)$
$x+2+6x$
$36:\left(-9\right)$
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