$6\left(\frac{b}{b+1}\right)^2+5\left(\frac{b}{b+1}\right)-6=0$
$\frac{4x^5-2x^3-x+6}{x^2+2x-1}$
$\frac{\:2\:cos\:\left(3x\right)}{sin\:\left(2x\right)}+\:\frac{sin\:\left(2x\right)}{cos\:\left(x\right)}=\:\frac{cos\:\left(2x\right)}{sin\:\left(x\right)}$
$40-3x\le10$
$16a^2m^3-24a^3m^2+32a^4$
$\lim_{x\to0}\left(\frac{e^x-e^{-x}}{x^2}\right)$
$5x^2+13x+12=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!