$2z\left(3x-3y-3z\right)$

$\left(x+8\right)\cdot\left(x+3\right)$

$x^2\left(-9x^2-10x\right)$

$2sin2\theta=3tan\theta\:$

$3x+4y=18$

$\lim_{x\to0}\left(\frac{\left(8^t\right)\cdot ln\left(8\right)-ln\left(2\right)\cdot2^{\left(2\cdot t+1\right)}}{4\cdot x}\right)$

$\left(-1\right).\left(-9\right)-\left(-4\right).8$