$\int\frac{1-x^3}{1-\sqrt[3]{x}}dx$
$1-x'=\frac{x-1}{x-2}$
$x^2-8x=9$
$\frac{dy}{dx}=\frac{y-2}{y+2}$
$y=x+5ln\left|x+1\right|+c$
$\frac{y}{\sqrt{1-y^2}}dy=xe^{-x}dx$
$5x^2\:para\:x=1$
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