$3\cdot sec^2x\cdot\left(1-sin^2x\right)$
$y'=\frac{\left(-x\right)}{y}$
$\frac{1}{4\:}\:x\:\frac{2}{3}$
$3x^2-4x-7=5x$
$4\cos\left(x\right)=\sin^2\left(x\right)+1$
$\int10sin^2xcos^2xdx$
$\int\left(\left(x^3+x\right)^5\left(3x^2+1\right)\right)dx$
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