$12+-6+-12+1$
$\int\left(3x^2+x-3\right)^6\left(6x+1\right)dx$
$\left(x-4\right)\:\frac{dy}{dx}=\:3y$
$\left(\sqrt[2]{x}+\frac{1}{3}\right)^4$
$m=\left(5x+4\right)^2$
$x^2+15x+26$
$\ln\left(x+2\right)-\ln4=-1$
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