$x^2-6x-7>0$
$45\cdot6$
$5y+\left(-3x\right)-6x+1-2y+9$
$\int\left(\frac{y^2}{\left(y^2+16\right)^{\frac{3}{2}}}\right)dx$
$1-\frac{\sin^{2}x}{\tan^{2}x}=\sin^{2}x$
$5\left(-6\right)+\left(-7\right)$
$-99-\left(-23\right)$
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