$x^3+13x^2+30x=0\:$
$\frac{dy}{dx}\left(y=x^{\text{4}}\left(x^3+4\right)^5\right)$
$\lim_{x\to-\infty}\left(\left(2^x+2\arctan\left(3x\right)\right)\right)$
$\left(-3\right)^4-\left(-2\right)^5-\left(-3\right)^3+\left(+5\right)^2-13^2$
$-3^2\left(6+4\right)$
$5\sin x-2\cos^2x-1=0$
$8x+5-6x-5-2x$
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