$\left(u-3\right)\left(u+3\right)$
$7x-14y-3=0$
$5x^2+9x=-4$
$\lim_{x\to1}\left(\frac{x^2-x}{x^2-3x+2}\right)$
$5^{-4^0}$
$\frac{dy}{dx}=\frac{4-2x}{3y^2-5};\:y\left(1\right)=3$
$\lim\:_{x\to\:-\infty\:}\left(\frac{cos^2x}{x}\right)$
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