$\lim_{x\to\infty}\left(\frac{2x^2+6}{3x^3+7}\right)$
$\int\left(9w^2+12w+4\right)^{\frac{4}{3}}dw$
$x-2y-3z=-1$
$\left(x^2-7x-9\right)\left(x^2+7x-9\right)$
$\frac{a-1}{1-a}$
$\frac{d^3\left(\frac{\left(3\right)}{\left(x-1\right)^2}\right)}{dx^3}$
$2\tan-\sec^2$
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